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发表于 2009-9-1 16:31:15
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#include <stdio.h>
- m( Z+ v; E/ i( l( o) i: I#include <string.h> ) a! z3 h3 W+ p9 ]0 M
#include <errno.h>
* p; E( ]' {7 q, k#include <unistd.h>
- o$ r3 T( n0 K9 }#include <fcntl.h>
- T5 C4 H. W' E; C( Y#include <linux/kd.h># I/ z% r- y6 o* M, x: [' J7 o4 R
#include <linux/keyboard.h> ' z( C7 [3 G" p7 v
#include <termios.h>
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#define KEY_DOWN 0x100
: H7 o8 `! d/ M6 x* e# X+ [7 N#define KEY_UP 0x000
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3 Z1 o f& S6 [% f: Z5 M- |int oldmode;
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struct termios new;
5 i7 d9 u' s3 W2 B+ k/ [. Ustruct termios old;
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int get_key_input(void)7 h" E' h3 H0 Q! k! w- w
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int keyboard;
5 ?- h! a8 D% E4 H7 K4 a& N7 uint keyboardcode;* c+ \% Q" w. t& m ~, W
- a' f& I( a6 D! E9 F# O J3 ~keyboard = init_keyboard();
1 [! a7 v t9 ~% y+ J: I# l* Bdo{
: e G. f; | @+ `. ]keyboardcode = poll_keyboard(keyboard); : [' G0 `3 w5 J; x) F4 V. ?
if((keyboardcode != 0) && (keyboardcode & KEY_DOWN)){
& ?2 |6 w4 o$ m! _# ^keyboardcode = keyboardcode & 0xFF;
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}while( keyboard != 0x58); 1 i( r2 H( I; L! H( o" [- F
exit_keyboard(keyboard);
. I* E; q4 s8 H) {8 j+ V# Qreturn 0;+ A0 l3 ]4 B9 x" v9 J7 ^# @* j
}
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int exit_keyboard(int keyboard)
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ioctl(keyboard, KDSKBMODE, oldmode);/ U- i2 \+ d# Q n
tcsetattr( keyboard, 0, &old);; e3 {3 g [. u" U% ?5 |
close(keyboard);; S" D6 e7 Z) V) ^
return 0;& C- \) l+ \+ c/ |# y
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int init_keyboard(void)1 G2 @5 n+ U! [" s# q$ p8 v
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int keyboard;
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! ]" G1 s# ^( |. Nkeyboard = open("/dev/tty", O_RDONLY);
& b b' n4 b- d9 Dioctl(keyboard, KDGKBMODE, &oldmode);
3 r- p$ W) c4 J5 d% z# e8 `; vtcgetattr( keyboard, &old);
; \4 g% n% @: R% J, t& P+ ntcgetattr( keyboard, &new);8 f% q7 e' s# J; Z, [0 r) u
5 G1 g% ~4 }4 {+ h, Qnew.c_lflag &= ~(ICANON | ECHO | ISIG);
0 D' B9 ?( x- h7 wnew.c_iflag = 0;. z' s" R5 {* v' P- Z) ~
new.c_cc[VMIN] = 0;
1 ~4 H! B, v/ Y6 L' \ @4 v' _new.c_cc[VTIME] = 1;% Y5 F/ v; M" S- d
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tcsetattr(keyboard, TCSAFLUSH, &new);0 M7 |) n e3 }, l! h3 j) Z
ioctl(keyboard, KDSKBMODE, K_RAW);
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return keyboard;
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int poll_keyboard(int keyboard) ! O4 U1 h# q- E* z* d8 A
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unsigned char buf[5];
: ~) e9 i7 O; c6 E6 fint n;$ V% T+ P" _: V8 Z+ D( I X, E
7 \4 R2 r+ r/ T5 g! B2 i& |int kc = 0;6 X; i$ |! `# w8 F7 [
int i = 0;5 \) v9 j# s* p4 n: t( e
int s = 0;2 A. g7 p) W( x8 A4 }- W3 v! B
n = read(keyboard, &buf, sizeof(buf)); , L! M4 [0 ?& p6 z9 r Q0 D% `
while( i < n){
8 Q. h- v. q8 b& B# m* B! E! Ps = (buf & 0x80) ? 0:1;" I, ? S% _& C& T1 Q7 m6 W9 P
s = s << 8;
. s3 z$ V7 `1 P6 U4 kif((i + 2) < n && (buf & 0x7F) == 0 && ( buf[i+1] & 0x80) != 0 && (buf[i+2] & 0x80) != 0){
; u _' [) I3 d: F2 Mkc = ((buf[i+1] & 0x7F ) << 7 ) |(buf[i+2] & 0x7F);- J0 X$ r- K& a4 r. k9 ~$ G- m% M, O. E
i += 3;% t: ~5 n% H6 k$ y7 L$ ~) H7 h- E5 L
}
2 C; o* Q4 E9 w$ U& Qelse{
7 }! J8 x' j7 p- w. t4 bkc = buf & 0x7F;
2 \: i, Z z& t& }i++;
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kc = s | kc;
4 i, A& B. f, h* Preturn kc;
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